Optimal. Leaf size=169 \[ -\frac{1}{2} c \text{PolyLog}\left (3,1-\frac{2}{1+i a x}\right )+\frac{1}{2} c \text{PolyLog}\left (3,-1+\frac{2}{1+i a x}\right )-i c \tan ^{-1}(a x) \text{PolyLog}\left (2,1-\frac{2}{1+i a x}\right )+i c \tan ^{-1}(a x) \text{PolyLog}\left (2,-1+\frac{2}{1+i a x}\right )+\frac{1}{2} c \log \left (a^2 x^2+1\right )+\frac{1}{2} a^2 c x^2 \tan ^{-1}(a x)^2+\frac{1}{2} c \tan ^{-1}(a x)^2-a c x \tan ^{-1}(a x)+2 c \tan ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac{2}{1+i a x}\right ) \]
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Rubi [A] time = 0.311247, antiderivative size = 169, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 10, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {4950, 4850, 4988, 4884, 4994, 6610, 4852, 4916, 4846, 260} \[ -\frac{1}{2} c \text{PolyLog}\left (3,1-\frac{2}{1+i a x}\right )+\frac{1}{2} c \text{PolyLog}\left (3,-1+\frac{2}{1+i a x}\right )-i c \tan ^{-1}(a x) \text{PolyLog}\left (2,1-\frac{2}{1+i a x}\right )+i c \tan ^{-1}(a x) \text{PolyLog}\left (2,-1+\frac{2}{1+i a x}\right )+\frac{1}{2} c \log \left (a^2 x^2+1\right )+\frac{1}{2} a^2 c x^2 \tan ^{-1}(a x)^2+\frac{1}{2} c \tan ^{-1}(a x)^2-a c x \tan ^{-1}(a x)+2 c \tan ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac{2}{1+i a x}\right ) \]
Antiderivative was successfully verified.
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Rule 4950
Rule 4850
Rule 4988
Rule 4884
Rule 4994
Rule 6610
Rule 4852
Rule 4916
Rule 4846
Rule 260
Rubi steps
\begin{align*} \int \frac{\left (c+a^2 c x^2\right ) \tan ^{-1}(a x)^2}{x} \, dx &=c \int \frac{\tan ^{-1}(a x)^2}{x} \, dx+\left (a^2 c\right ) \int x \tan ^{-1}(a x)^2 \, dx\\ &=\frac{1}{2} a^2 c x^2 \tan ^{-1}(a x)^2+2 c \tan ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac{2}{1+i a x}\right )-(4 a c) \int \frac{\tan ^{-1}(a x) \tanh ^{-1}\left (1-\frac{2}{1+i a x}\right )}{1+a^2 x^2} \, dx-\left (a^3 c\right ) \int \frac{x^2 \tan ^{-1}(a x)}{1+a^2 x^2} \, dx\\ &=\frac{1}{2} a^2 c x^2 \tan ^{-1}(a x)^2+2 c \tan ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac{2}{1+i a x}\right )-(a c) \int \tan ^{-1}(a x) \, dx+(a c) \int \frac{\tan ^{-1}(a x)}{1+a^2 x^2} \, dx+(2 a c) \int \frac{\tan ^{-1}(a x) \log \left (\frac{2}{1+i a x}\right )}{1+a^2 x^2} \, dx-(2 a c) \int \frac{\tan ^{-1}(a x) \log \left (2-\frac{2}{1+i a x}\right )}{1+a^2 x^2} \, dx\\ &=-a c x \tan ^{-1}(a x)+\frac{1}{2} c \tan ^{-1}(a x)^2+\frac{1}{2} a^2 c x^2 \tan ^{-1}(a x)^2+2 c \tan ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac{2}{1+i a x}\right )-i c \tan ^{-1}(a x) \text{Li}_2\left (1-\frac{2}{1+i a x}\right )+i c \tan ^{-1}(a x) \text{Li}_2\left (-1+\frac{2}{1+i a x}\right )+(i a c) \int \frac{\text{Li}_2\left (1-\frac{2}{1+i a x}\right )}{1+a^2 x^2} \, dx-(i a c) \int \frac{\text{Li}_2\left (-1+\frac{2}{1+i a x}\right )}{1+a^2 x^2} \, dx+\left (a^2 c\right ) \int \frac{x}{1+a^2 x^2} \, dx\\ &=-a c x \tan ^{-1}(a x)+\frac{1}{2} c \tan ^{-1}(a x)^2+\frac{1}{2} a^2 c x^2 \tan ^{-1}(a x)^2+2 c \tan ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac{2}{1+i a x}\right )+\frac{1}{2} c \log \left (1+a^2 x^2\right )-i c \tan ^{-1}(a x) \text{Li}_2\left (1-\frac{2}{1+i a x}\right )+i c \tan ^{-1}(a x) \text{Li}_2\left (-1+\frac{2}{1+i a x}\right )-\frac{1}{2} c \text{Li}_3\left (1-\frac{2}{1+i a x}\right )+\frac{1}{2} c \text{Li}_3\left (-1+\frac{2}{1+i a x}\right )\\ \end{align*}
Mathematica [A] time = 0.0439985, size = 177, normalized size = 1.05 \[ \frac{1}{2} c \text{PolyLog}\left (3,\frac{-a x-i}{a x-i}\right )-\frac{1}{2} c \text{PolyLog}\left (3,\frac{a x+i}{a x-i}\right )+i c \tan ^{-1}(a x) \text{PolyLog}\left (2,\frac{-a x-i}{a x-i}\right )-i c \tan ^{-1}(a x) \text{PolyLog}\left (2,\frac{a x+i}{a x-i}\right )+\frac{1}{2} c \log \left (a^2 x^2+1\right )+\frac{1}{2} c \left (a^2 x^2+1\right ) \tan ^{-1}(a x)^2-a c x \tan ^{-1}(a x)+2 c \tan ^{-1}(a x)^2 \tanh ^{-1}\left (1-\frac{2 i}{-a x+i}\right ) \]
Antiderivative was successfully verified.
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Maple [C] time = 1.577, size = 1078, normalized size = 6.4 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{8} \, a^{2} c x^{2} \arctan \left (a x\right )^{2} - \frac{1}{32} \, a^{2} c x^{2} \log \left (a^{2} x^{2} + 1\right )^{2} + 12 \, a^{4} c \int \frac{x^{4} \arctan \left (a x\right )^{2}}{16 \,{\left (a^{2} x^{3} + x\right )}}\,{d x} + a^{4} c \int \frac{x^{4} \log \left (a^{2} x^{2} + 1\right )^{2}}{16 \,{\left (a^{2} x^{3} + x\right )}}\,{d x} + 2 \, a^{4} c \int \frac{x^{4} \log \left (a^{2} x^{2} + 1\right )}{16 \,{\left (a^{2} x^{3} + x\right )}}\,{d x} - 4 \, a^{3} c \int \frac{x^{3} \arctan \left (a x\right )}{16 \,{\left (a^{2} x^{3} + x\right )}}\,{d x} + 24 \, a^{2} c \int \frac{x^{2} \arctan \left (a x\right )^{2}}{16 \,{\left (a^{2} x^{3} + x\right )}}\,{d x} + \frac{1}{48} \, c \log \left (a^{2} x^{2} + 1\right )^{3} + 12 \, c \int \frac{\arctan \left (a x\right )^{2}}{16 \,{\left (a^{2} x^{3} + x\right )}}\,{d x} + c \int \frac{\log \left (a^{2} x^{2} + 1\right )^{2}}{16 \,{\left (a^{2} x^{3} + x\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (a^{2} c x^{2} + c\right )} \arctan \left (a x\right )^{2}}{x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} c \left (\int \frac{\operatorname{atan}^{2}{\left (a x \right )}}{x}\, dx + \int a^{2} x \operatorname{atan}^{2}{\left (a x \right )}\, dx\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a^{2} c x^{2} + c\right )} \arctan \left (a x\right )^{2}}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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